16 September 2023

• 14:4414:44, 16 September 2023 diff hist +2 1981 AHSME Problems Fixed a conflict between the problem text here and in the solution. The problem written here used the identity f(x) + f(1/x) = x, but if we let y = 1/x, then f(1/y) + f(y) = 1/y for all nonzero real y, so we would arrive at the contradiction that x=1/x.

29 October 2021

• 20:3420:34, 29 October 2021 diff hist −121 1990 AJHSME Problems/Problem 21 removed a vague solution