Art of Problem Solving

2025 AMC 12A Problems/Problem 17

The polynomial $(z+i)(z+2i)(z+3i) + 10$ has three roots in the complex plane. What is the area of the triangle formed by these roots?

Solution 1 (Symmetry)

Let $w$ be a complex number such that $w=z+2i,$ then we can change our polynomial to the following, \[(z+i)(z+2i)(z+3i) + 10 = (c-i)(c)(c+i)+10 = c^3 +c+10 = 0.\] Notice $c = -2$ is a root, and from this we get a quadratic and find the the possible values of $c = -2, 1\pm 2i.$


Now we simply subtract $2i$ from each root to get the roots to be $z = -2-2i, 1 + 0i,$ and $1 - 4i.$


Moving back to the coordinate plane our points are $(-2,-2), (1,-4),$ and $(1,0),$ and using shoelace gives us an area of $\boxed{6,\textbf{A.}}$


~mathkiddus

See Also

2025 AMC 10A (ProblemsAnswer KeyResources)
Preceded by
First Problem
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions
2025 AMC 12A (ProblemsAnswer KeyResources)
Preceded by
First Problem
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions

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