2001 CEMC Gauss (Grade 8) Problems/Problem 4

Problem

When a number is divided by $7$ , the quotient is $12$ and the remainder is $5$ . The number is

$\text{ (A) }\ 47 \qquad\text{ (B) }\ 79 \qquad\text{ (C) }\ 67 \qquad\text{ (D) }\ 119 \qquad\text{ (E) }\ 89$

Let $n$ be the dividend/number. From the remainder, divisor, and quotient given in the problem, we have:

$n = 12 \times 7 + 5 = 84 + 5 = \boxed {\textbf {(E) } 89}$

~anabel.disher

2001 CEMC Gauss (Grade 8) (Problems • Answer Key • Resources)
Preceded by Problem 3	Followed by Problem 5
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CEMC Gauss (Grade 8)