2020 AMC 12A Problems/Problem 13
Problem
There are integers
and
each greater than
such that
Solution
can be simplified to $N^{\frac{1}{a}+\frac{1}{ab}+\frac{1}{abc}}.
The equation is then$ (Error compiling LaTeX. Unknown error_msg)N^{\frac{1}{a}+\frac{1}{ab}+\frac{1}{abc}}=N^{frac{25}{36}}
\frac{1}{a}+\frac{1}{ab}+\frac{1}{abc}=\frac{25}{36}.
has to be
since
.
being
will make the fraction
which is close to
. Finally, with
being
, the fraction becomes
. In this case
and
work, which means that
must equal
~lopkiloinm