1959 AHSME Problems/Problem 22: Difference between revisions
Created page with "Let x be the length of the shorter base. 3 = (97 - x)/2 6 = 97 - x x = 91 Thus, 91." |
No edit summary |
||
| Line 1: | Line 1: | ||
Let x be the length of the shorter base. | Let x be the length of the shorter base. | ||
3 = (97 - x)/2 | 3 = (97 - x)/2 | ||
6 = 97 - x | 6 = 97 - x | ||
x = 91 | x = 91 | ||
Thus, 91. | Thus, 91. | ||
Revision as of 09:29, 22 August 2018
Let x be the length of the shorter base. 3 = (97 - x)/2
6 = 97 - x
x = 91
Thus, 91.
