MIE 2016/Problem 2: Difference between revisions

Revision as of 20:20, 7 January 2018

The following system has $k$ integer solutions. We can say that:

$\begin{cases}\frac{x^2-2x-14}{x}>3\\\\x\leq12\end{cases}$

(a) $0\leq k\leq 2$

(b) $2\leq k\leq 4$

(c) $4\leq k\leq6$

(d) $6\leq k\leq8$

(e) $k\geq8$

@@ Line 15: / Line 15: @@
 (e) <math>k\geq8</math>
-===Solution 2===
+==Solution 2==
 ===See Also===