MIE 2016/Problem 2: Difference between revisions

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The following system has $k$ integer solutions. We can say that:

$\begin{cases}\frac{x^2-2x-14}{x}>3\\\\x\leq12\end{cases}$

(a) $0\leq k\leq 2$

(b) $2\leq k\leq 4$

(c) $4\leq k\leq6$

(d) $6\leq k\leq8$

(e) $k\geq8$

Revision as of 20:19, 7 January 2018 view source Anishanne (talk \| contribs) editor 155 edits Created page with "===Problem 2=== The following system has <math>k</math> integer solutions. We can say that: <math>\begin{cases}\frac{x^2-2x-14}{x}>3\\\\x\leq12\end{cases}</math> (a) <math>..."		Revision as of 20:20, 7 January 2018 view source Anishanne (talk \| contribs) editor 155 edits →Problem 2 Newer edit →
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	===Problem 2===		==Problem 2==
	The following system has <math>k</math> integer solutions. We can say that:		The following system has <math>k</math> integer solutions. We can say that: