Art of Problem Solving

1983 IMO Problems/Problem 5: Difference between revisions

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==Problem 5==
==Problem 5==
Is it possible to choose <math>1983</math> distinct positive integers, all less than or equal to <math>10^5</math>, no three of which are consecutive terms of an arithmetic progression? Justify your answer.
Is it possible to choose <math>1983</math> distinct positive integers, all less than or equal to <math>10^5</math>, no three of which are consecutive terms of an arithmetic progression? Justify your answer.
==Solution==

Revision as of 16:30, 22 August 2017

Problem 5

Is it possible to choose $1983$ distinct positive integers, all less than or equal to $10^5$, no three of which are consecutive terms of an arithmetic progression? Justify your answer.

Solution