Besot Power Series: Difference between revisions

Revision as of 14:51, 17 February 2016

Besot's Power Series Theorem states that $\sum\limits_{i=1}^m n^{a+(i-1)z} = \frac{n^{a+mz}-n^a}{n^z-1}$

Let there be a sum $n^a + n^{a+z} + ... n^{a+(m-1)z} = \sum\limits_{i=1}^m n^{a+(i-1)z} = s$

$s = \sum\limits_{i=1}^m n^{a+(i-1)z}$

$sn^z = \sum\limits_{i=1}^m n^{a+iz}$

$sn^z-s = \sum\limits_{i=1}^m n^{a+iz} - \sum\limits_{i=1}^m n^{a+(i-1)z}$

$s(n^z-1) = n^{a+mz}-n^a$

$s = \frac{n^{a+mz}-n^a}{n^z-1}$

$\boxed{\frac{n^{a+mz}-n^a}{n^z-1}}$

What is $2^3+2^5+2^7?$

$\sum\limits_{i=1}^{2016} n^i = n^{2017}$ . What is $n$ ?

@@ Line 24: / Line 24: @@
 ===Problem 1===
-What is <math>8(3^3+3^5+3^7+3^9)+27</math>
+What is <math>2^3+2^5+2^7?</math>
 ===Problem 2===
 <math>\sum\limits_{i=1}^{2016} n^i = n^{2017}</math>. What is <math>n</math>?