2006 AMC 12A Problems/Problem 5: Difference between revisions
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== Solution == | == Solution == | ||
Each slice of plain pizza costs <math>\frac{1}{8}\cdot 8=1</math> dollar. Each slice of anchovy pizza costs <math>1+\frac{1}{4}\cdot 2=\frac{3}{2}</math> dollars. Dave paid <math>4\cdot\frac{3}{2}+1\cdot 1=7</math> dollars, and Doug paid <math>3\cdot 1=3</math> dollars. Dave paid <math>7-3=4</math> dollars than Doug. The answer is D. | |||
== See also == | == See also == | ||
* [[2006 AMC 12A Problems]] | * [[2006 AMC 12A Problems]] | ||
Revision as of 12:56, 12 July 2006
Problem
Doug and Dave shared a pizza with 
equally-sized slices. Doug wanted a plain pizza, but Dave wanted anchovies on half the pizza. The cost of a plain pizza was , and there was an additional cost of 
for putting anchovies on one half. Dave ate all the slices of anchovy pizza and one plain slice. Doug ate the remainder. Each paid for what he had eaten. How many more dollars did Dave pay than Doug?
Solution
Each slice of plain pizza costs 
dollar. Each slice of anchovy pizza costs 
dollars. Dave paid 
dollars, and Doug paid 
dollars. Dave paid 
dollars than Doug. The answer is D.
