Art of Problem Solving

1952 AHSME Problems/Problem 50: Difference between revisions

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== See also ==
== See also ==
{{AHSME 50p box|year=1952|num-b=49|num-a=50}}   
{{AHSME 50p box|year=1952|num-b=49|after=Last Question}}   


[[Category: Intermediate Algebra Problems]]
[[Category: Intermediate Algebra Problems]]
{{MAA Notice}}
{{MAA Notice}}

Revision as of 17:00, 18 July 2015

Problem

A line initially 1 inch long grows according to the following law, where the first term is the initial length. \[1+\frac{1}{4}\sqrt{2}+\frac{1}{4}+\frac{1}{16}\sqrt{2}+\frac{1}{16}+\frac{1}{64}\sqrt{2}+\frac{1}{64}+\cdots\]

If the growth process continues forever, the limit of the length of the line is:

$\textbf{(A) } \infty\qquad \textbf{(B) } \frac{4}{3}\qquad \textbf{(C) } \frac{8}{3}\qquad \textbf{(D) } \frac{1}{3}(4+\sqrt{2})\qquad \textbf{(E) } \frac{2}{3}(4+\sqrt{2})$

Solution

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See also

1952 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 49
Followed by
Last Question
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