Art of Problem Solving

1991 AHSME Problems/Problem 6: Difference between revisions

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== Problem ==
If <math>x\geq 0</math>, then <math>\sqrt{x\sqrt{x\sqrt{x}}}=</math>
If <math>x\geq 0</math>, then <math>\sqrt{x\sqrt{x\sqrt{x}}}=</math>


(A) <math>x\sqrt{x}</math> (B) <math>x \sqrt[4]{x}</math> (C) <math>\sqrt[8]{x}</math> (D) <math>\sqrt[8]{x^3}</math> (E) <math>\sqrt[8]{x^7}</math>
(A) <math>x\sqrt{x}</math> (B) <math>x \sqrt[4]{x}</math> (C) <math>\sqrt[8]{x}</math> (D) <math>\sqrt[8]{x^3}</math> (E) <math>\sqrt[8]{x^7}</math>
== Solution ==
<math>\fbox{}</math>
== See also ==
{{AHSME box|year=1991|num-b=5|num-a=7}} 
[[Category: Introductory Algebra Problems]]
{{MAA Notice}}
{{MAA Notice}}

Revision as of 02:11, 28 September 2014

Problem

If $x\geq 0$, then $\sqrt{x\sqrt{x\sqrt{x}}}=$

(A) $x\sqrt{x}$ (B) $x \sqrt[4]{x}$ (C) $\sqrt[8]{x}$ (D) $\sqrt[8]{x^3}$ (E) $\sqrt[8]{x^7}$

Solution

$\fbox{}$

See also

1991 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 5
Followed by
Problem 7
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
All AHSME Problems and Solutions

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