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Divisibility rules/Rule for 17 proof: Difference between revisions

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''[[Divisibility_rules#Divisibility_Rule_for_17 | Back to main article]]''
''[[Divisibility_rules#Divisibility_Rule_for_17 | Back to main article]]''
[[Category:Divisibility Rules]]

Latest revision as of 19:29, 6 March 2014

If the rule is $5n_0-k$ (the opposite of the suggested rule $k-5n_0$, but that is proven in turn, and $k=n_110^0+n_210^1+n_310^2+...$) we know that :

$5n_0-k\equiv 5n_0+16k\equiv 5n_0+33k\equiv 5n_0+50k\equiv n_0+10k$, which is our original number.


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