Art of Problem Solving

2014 AMC 10B Problems/Problem 20: Difference between revisions

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==Problem==
==Problem==
For how many integers <math>x</math> is the number <math>x^4-51x^2+50</math> negative?
For how many integers <math>x</math> is the number <math>x^4-51x^2+50</math> negative?
<math> \textbf {(A) } 8 \qquad \textbf {(B) } 10 \qquad \textbf {(C) } 12 \qquad \textbf {(D) } 14 \qquad \textbf {(E) } 16</math>


==Solution==
==Solution==

Revision as of 13:26, 20 February 2014

Problem

For how many integers $x$ is the number $x^4-51x^2+50$ negative?

$\textbf {(A) } 8 \qquad \textbf {(B) } 10 \qquad \textbf {(C) } 12 \qquad \textbf {(D) } 14 \qquad \textbf {(E) } 16$

Solution

See Also

2014 AMC 10B (ProblemsAnswer KeyResources)
Preceded by
Problem 19
Followed by
Problem 21
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All AMC 10 Problems and Solutions

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