2006 AIME I Problems/Problem 4: Difference between revisions

Revision as of 20:24, 4 July 2006

Problem

Let $N$ be the number of consecutive 0's at the right end of the decimal representation of the product $1!2!3!4!\cdots99!100!.$ Find the remainder when $N$ is divided by 1000.

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2006 AIME I Problems/Problem 4: Difference between revisions

Revision as of 20:24, 4 July 2006

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Revision as of 11:13, 30 June 2006 view source MCrawford (talk \| contribs) 1,942 edits mNo edit summary ← Older edit	Revision as of 20:24, 4 July 2006 view source Joml88 (talk \| contribs) 1,619 edits m 2006 AIME I Problem 4 moved to 2006 AIME I Problems/Problem 4 Newer edit →
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