Art of Problem Solving

1991 AHSME Problems/Problem 20: Difference between revisions

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(A) 3/2  (B) 2  (C) 5/2  (D) 3  (E) 7/2
(A) 3/2  (B) 2  (C) 5/2  (D) 3  (E) 7/2
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The sum of all real $x$ such that $(2^x-4)^3+(4^x-2)^3=(4^x+2^x-6)^3$ is

(A) 3/2 (B) 2 (C) 5/2 (D) 3 (E) 7/2 These problems are copyrighted © by the Mathematical Association of America.