1991 AHSME Problems/Problem 14: Difference between revisions
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(A) <math>200</math> (B) <math>201</math> (C) <math>202</math> (D) <math>203</math> (E) <math>204</math> | (A) <math>200</math> (B) <math>201</math> (C) <math>202</math> (D) <math>203</math> (E) <math>204</math> | ||
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Revision as of 12:53, 5 July 2013
If 
is the cube of a positive integer and 
is the number of positive integers that are divisors of , then could be
(A) 
(B) 
(C) 
(D) 
(E) 
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