1992 AJHSME Problems/Problem 7: Difference between revisions

Revision as of 23:09, 4 July 2013

Problem

The digit-sum of $998$ is $9+9+8=26$ . How many 3-digit whole numbers, whose digit-sum is $26$ , are even?

$\text{(A)}\ 1 \qquad \text{(B)}\ 2 \qquad \text{(C)}\ 3 \qquad \text{(D)}\ 4 \qquad \text{(E)}\ 5$

Solution

The hightest digit sum for three-digit numbers is $9+9+9=27$ . Therefore, the only possible digit combination is $9, 9, 8$ . Of course, of the three possible numbers, only $998$ works. Thus, the answer is $\boxed{\text{(A)}\ 1}$ .

1992 AJHSME (Problems • Answer Key • Resources)
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All AJHSME/AMC 8 Problems and Solutions

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1992 AJHSME Problems/Problem 7: Difference between revisions

Revision as of 23:09, 4 July 2013

Problem

Solution

See Also