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1989 AJHSME Problems/Problem 12: Difference between revisions

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New page: ==Problem== <math>\frac{1-\frac{1}{3}}{1-\frac{1}{2}} =</math> <math>\text{(A)}\ \frac{1}{3} \qquad \text{(B)}\ \frac{2}{3} \qquad \text{(C)}\ \frac{3}{4} \qquad \text{(D)}\ \frac{3}{2} ...
 
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{{AJHSME box|year=1989|num-b=11|num-a=13}}
{{AJHSME box|year=1989|num-b=11|num-a=13}}
[[Category:Introductory Algebra Problems]]
[[Category:Introductory Algebra Problems]]
{{MAA Notice}}

Latest revision as of 22:57, 4 July 2013

Problem

$\frac{1-\frac{1}{3}}{1-\frac{1}{2}} =$

$\text{(A)}\ \frac{1}{3} \qquad \text{(B)}\ \frac{2}{3} \qquad \text{(C)}\ \frac{3}{4} \qquad \text{(D)}\ \frac{3}{2} \qquad \text{(E)}\ \frac{4}{3}$

Solution

\begin{align*} \frac{1-\frac{1}{3}}{1-\frac{1}{2}} &= \frac{\frac{2}{3}}{\frac{1}{2}} \\ &= \frac{2}{3} \times 2 \\ &= \frac{4}{3} \rightarrow \boxed{\text{E}} \end{align*}

See Also

1989 AJHSME (Problems • Answer Key • Resources)
Preceded by
Problem 11 		Followed by
Problem 13
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions

These problems are copyrighted © by the Mathematical Association of America.

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