2001 AMC 12 Problems/Problem 9: Difference between revisions

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Let $f$ be a function satisfying $f(xy) = \frac{f(x)}y$ for all positive real numbers $x$ and $y$ . If $f(500) =3$ , what is the value of $f(600)$ ?

$(\mathrm{A})\ 1 \qquad (\mathrm{B})\ 2 \qquad (\mathrm{C})\ \frac52 \qquad (\mathrm{D})\ 3 \qquad (\mathrm{E})\ \frac{18}5$

$f(500\cdot\frac65) = \frac3{\frac65} = \frac52$ , so the answer is $\boxed{\mathrm{C}}$ .

2001 AMC 12 (Problems • Answer Key • Resources)
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All AMC 12 Problems and Solutions

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