Art of Problem Solving

1950 AHSME Problems/Problem 23: Difference between revisions

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==Problem==
==Problem==
A man buys a house for &#036;10,000 and rents it. He puts <math>12\frac{1}{2}\%</math> of each month's rent aside for repairs and upkeep; pays  &#036;325 a year taxes and realizes <math>5\frac{1}{2}\%</math> on his investment. The monthly rent (in dollars) is:
A man buys a house for &#036;10,000 and rents it. He puts <math>12\frac{1}{2}\%</math> of each month's rent aside for repairs and upkeep; pays  &#036;325 a year taxes and realizes <math>5\frac{1}{2}\%</math> on his investment. The monthly rent (in dollars) is:


<math> \textbf{(A)}\ \64.82\qquad\textbf{(B)}\ \83.33\qquad\textbf{(C)}\ \72.08\qquad\textbf{(D)}\ \45.83\qquad\textbf{(E)}\ \177.08 </math>
<math> \textbf{(A)}\ \64.82\qquad\textbf{(B)}\ \83.33\qquad\textbf{(C)}\ \72.08\qquad\textbf{(D)}\ \45.83\qquad\textbf{(E)}\ \177.08 </math>


== Solution ==
{{solution}}
{{solution}}


== See Also ==
{{AHSME box|year=1950|num-b=22|num-a=24}}
{{AHSME box|year=1950|num-b=22|num-a=24}}
[[Category:Introductory Algebra Problems]]

Revision as of 13:21, 17 April 2012

Problem

A man buys a house for $10,000 and rents it. He puts $12\frac{1}{2}\%$ of each month's rent aside for repairs and upkeep; pays $325 a year taxes and realizes $5\frac{1}{2}\%$ on his investment. The monthly rent (in dollars) is:

$\textbf{(A)}\ \64.82\qquad\textbf{(B)}\ \83.33\qquad\textbf{(C)}\ \72.08\qquad\textbf{(D)}\ \45.83\qquad\textbf{(E)}\ \177.08$ (Error compiling LaTeX. Unknown error_msg)

Solution

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See Also

1950 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 22
Followed by
Problem 24
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All AHSME Problems and Solutions