2012 AMC 12B Problems/Problem 2: Difference between revisions
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== Problem== | == Problem== | ||
A circle of radius 5 is inscribed in a rectangle as shown. The ratio of the length of the rectangle to it's width is 2:1. What is the area of the rectangle | A circle of radius 5 is inscribed in a rectangle as shown. The ratio of the length of the rectangle to it's width is 2:1. What is the area of the rectangle | ||
==Solution== | |||
If the radius is 5, then the width is 10, hence the length is 20. 10x20=200, E | |||
Revision as of 20:15, 23 February 2012
Problem
A circle of radius 5 is inscribed in a rectangle as shown. The ratio of the length of the rectangle to it's width is 2:1. What is the area of the rectangle
Solution
If the radius is 5, then the width is 10, hence the length is 20. 10x20=200, E
