2000 AMC 8 Problems/Problem 1: Difference between revisions

Revision as of 17:15, 30 July 2011

Aunt Anna is $42$ years old. Caitlin is $5$ years younger than Brianna, and Brianna is half as old as Aunt Anna. How old is Caitlin?

$\mathrm{(A)}\ 15 \qquad \mathrm{(B)}\ 16 \qquad \mathrm{(C)}\ 17 \qquad \mathrm{(D)}\ 21 \qquad \mathrm{(E)}\ 37$

If Brianna is half as old as Aunt Anna, then Briana is $\frac{42}{2}$ years old, or $21$ years old.

If Caitlin is $5$ years younger than Briana, she is $21-5$ years old, or $16$ .

So, the answer is $\boxed{B}$

2000 AMC 8 (Problems • Answer Key • Resources)
Preceded by First Question	Followed by Problem 2
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All AJHSME/AMC 8 Problems and Solutions

@@ Line 14: / Line 14: @@
 </math>
 == Solution ==
-If Brianna is half as old as Aunt Anna, then Briana is <math>42/2</math> years old, or <math>21</math> years old.
+If Brianna is half as old as Aunt Anna, then Briana is <math>\frac{42}{2}</math> years old, or <math>21</math> years old.
 If Caitlin is <math>5</math> years younger than Briana, she is <math>21-5</math> years old, or <math>16</math>.