1992 AJHSME Problems/Problem 7: Difference between revisions
Math Kirby (talk | contribs) Created page with "== Problem 7 == The digit-sum of <math>998</math> is <math>9+9+8=26</math>. How many 3-digit whole numbers, whose digit-sum is <math>26</math>, are even? <math>\text{(A)}\ 1 \..." |
Math Kirby (talk | contribs) |
||
| Line 1: | Line 1: | ||
== Problem | == Problem== | ||
The digit-sum of <math>998</math> is <math>9+9+8=26</math>. How many 3-digit whole numbers, whose digit-sum is <math>26</math>, are even? | The digit-sum of <math>998</math> is <math>9+9+8=26</math>. How many 3-digit whole numbers, whose digit-sum is <math>26</math>, are even? | ||
Revision as of 15:24, 29 July 2011
Problem
The digit-sum of 
is 
. How many 3-digit whole numbers, whose digit-sum is 
, are even?
Solution
The hightest digit sum for three-digit numbers is 
. Therefore, the only possible digit combination is 
. Of course, of the three possible numbers, only works. Thus, the answer is 
.
