2005 AMC 8 Problems/Problem 5: Difference between revisions

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If $20\%$ of a number is $12$ , what is $30\%$ of the same number?

$\mathrm{(A)}\ 15\qquad\mathrm{(B)}\ 18 \qquad\mathrm{(C)}\ 20 \qquad\mathrm{(D)}\ 24 \qquad\mathrm{(E)}\ 30$

Since $20 \%$ of a number is $12$ , then $10 \%$ of the number is $6$ , so $30\%$ of the number is $\boxed{\mathrm{(B)}\ 18}$ .

Revision as of 09:03, 29 July 2011 view source Math Kirby (talk \| contribs) editor 260 edits Created page with "==Problem 5== If <math> 20\% </math> of a number is <math>12</math>, what is <math> 30\% </math> of the same number? <math>\mathrm{(A)}\ 15\qquad\mathrm{(B)}\ 18 \qquad\mathrm{(..."		Revision as of 15:23, 29 July 2011 view source Math Kirby (talk \| contribs) editor 260 edits m →Problem 5 Newer edit →
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	==Problem 5==		==Problem==
	If <math> 20\% </math> of a number is <math>12</math>, what is <math> 30\% </math> of the same number?		If <math> 20\% </math> of a number is <math>12</math>, what is <math> 30\% </math> of the same number?