Art of Problem Solving

2011 AMC 12A Problems/Problem 13: Difference between revisions

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== Problem ==
== Problem ==
Triangle <math>ABC</math> has side-lengths <math>AB = 12, BC = 24,</math> and <math>AC = 18.</math> The line through the incenter of <math>\triangle ABC</math> parallel to <math>\overline{BC}</math> intersects <math>\overline{AB}</math> at <math>M</math> and <math>\overbar{AC}</math> at <math>N.</math> What is the perimeter of <math>\triangle AMN?</math>
<math>
\textbf{(A)}\ 27 \qquad
\textbf{(B)}\ 30 \qquad
\textbf{(C)}\  33 \qquad
\textbf{(D)}\ 36 \qquad
\textbf{(E)}\ 42 </math>
== Solution ==
== Solution ==
== See also ==
== See also ==
{{AMC12 box|year=2011|num-b=12|num-a=14|ab=A}}
{{AMC12 box|year=2011|num-b=12|num-a=14|ab=A}}

Revision as of 01:34, 10 February 2011

Problem

Triangle $ABC$ has side-lengths $AB = 12, BC = 24,$ and $AC = 18.$ The line through the incenter of $\triangle ABC$ parallel to $\overline{BC}$ intersects $\overline{AB}$ at $M$ and $\overbar{AC}$ (Error compiling LaTeX. Unknown error_msg) at $N.$ What is the perimeter of $\triangle AMN?$

$\textbf{(A)}\ 27 \qquad \textbf{(B)}\ 30 \qquad \textbf{(C)}\  33 \qquad \textbf{(D)}\ 36 \qquad \textbf{(E)}\ 42$

Solution

See also

2011 AMC 12A (ProblemsAnswer KeyResources)
Preceded by
Problem 12
Followed by
Problem 14
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions