Art of Problem Solving

2006 Romanian NMO Problems/Grade 7/Problem 2: Difference between revisions

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A square of side <math>n</math> is formed from <math>n^2</math> unit squares, each colored in red, yellow or green. Find minimal <math>n</math>, such that for each coloring, there exists a line and a column with at least 3 unit squares of the same color (on the same line or column).
A square of side <math>n</math> is formed from <math>n^2</math> unit squares, each colored in red, yellow or green. Find minimal <math>n</math>, such that for each coloring, there exists a line and a column with at least 3 unit squares of the same color (on the same line or column).
==Solution==
==Solution==
{{solution}}
For <math>nleq6</math>, consider this coloring for a 6x6 board:
 
RYGRYG
GRYGRY
YGRYGR
RYGRYG
GRYGRY
YGRYGR
 
We can take the top <math>n</math>-by-<math>n</math> grid of this board as a coloring not satisfying the conditions.
For <math>n\geq7</math>, we note that each row or column must have at least one color with 3 or more squares by the pigeonhole principle, so our answer is 7.


==See also==
==See also==
*[[2006 Romanian NMO Problems]]
*[[2006 Romanian NMO Problems]]
[[Category:Olympiad Combinatorics Problems]]
[[Category:Olympiad Combinatorics Problems]]

Revision as of 01:46, 18 March 2009

Problem

A square of side $n$ is formed from $n^2$ unit squares, each colored in red, yellow or green. Find minimal $n$, such that for each coloring, there exists a line and a column with at least 3 unit squares of the same color (on the same line or column).

Solution

For $nleq6$, consider this coloring for a 6x6 board:

RYGRYG GRYGRY YGRYGR RYGRYG GRYGRY YGRYGR

We can take the top $n$-by-$n$ grid of this board as a coloring not satisfying the conditions. For $n\geq7$, we note that each row or column must have at least one color with 3 or more squares by the pigeonhole principle, so our answer is 7.

See also