2000 AMC 10 Problems/Problem 9: Difference between revisions
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==Problem== | |||
==Solution== | |||
<math>|x-2|=p</math> | <math>|x-2|=p</math> | ||
<math>x<2</math>, so <math>2-x=p</math>. | <math>x<2</math>, so <math>2-x=p</math>. | ||
<math>x+p=2</math>. | <math>x+p=2</math>. | ||
<math>x-p=2-2p</math>. | <math>x-p=2-2p</math>. | ||
C | <math>\boxed{\text{C}}</math> | ||
Revision as of 18:36, 8 January 2009
Problem
Solution
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