2025 AMC 12A Problems/Problem 7: Difference between revisions
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Taking the logarithm of both sides and using n = 5, we have: | Taking the logarithm of both sides and using n = 5, we have: | ||
<imath>log</imath> <imath>k</imath> * 5^am^b<imath> = < | <imath>log</imath> <imath>k</imath> * <imath>5^am^b</imath> = <imath>4+2logm</imath> | ||
Revision as of 16:37, 6 November 2025
Solution 1: Taking the logarithm of both sides and using n = 5, we have:
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