Art of Problem Solving

2025 AMC 12A Problems/Problem 7: Difference between revisions

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Taking the logarithm of both sides and using n = 5, we have:
Taking the logarithm of both sides and using n = 5, we have:


<imath>log</imath> <imath> k5^am^b</imath> = <imath>4+2logm</imath>
<imath>log</imath> <imath>k</imath> * 5^am^b<imath> = </imath>4+2logm$

Revision as of 16:36, 6 November 2025

Solution 1: Taking the logarithm of both sides and using n = 5, we have:

$log$ $k$ * 5^am^b$=$4+2logm$