Art of Problem Solving

2025 AMC 12A Problems/Problem 7: Difference between revisions

Cyrus825 (talk | contribs)
No edit summary
Cyrus825 (talk | contribs)
No edit summary
Line 1: Line 1:
Solution 1:
Solution 1:
Taking the logarithm of both sides in the first equation, we have:
log v = log k<imath>n^a</imath> <imath>m^b</imath>

Revision as of 16:33, 6 November 2025

Solution 1: Taking the logarithm of both sides in the first equation, we have:

log v = log k$n^a$ $m^b$