2025 AMC 10A Problems/Problem 17: Difference between revisions
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==Solution 1== | ==Solution 1== | ||
The problem statement implies <imath>N|273420</imath> and <imath>N|272745.</imath> We want to find <imath>N > 16</imath> that satisfies both of these conditions. Hence, we can just find the greatest common divisor of the two numbers. <imath>\gcd | The problem statement implies <imath>N|273420</imath> and <imath>N|272745.</imath> We want to find <imath>N > 16</imath> that satisfies both of these conditions. Hence, we can just find the greatest common divisor of the two numbers. <imath>\gcd(273420,272745)=\gcd(675,272745)=\gcd(675,45)=45,</imath> so the answer is <imath>\boxed{\text{(E) }4}.</imath> | ||
~Tacos_are_yummy_1 | ~Tacos_are_yummy_1 | ||
Revision as of 12:48, 6 November 2025
(Problem goes here)
Solution 1
The problem statement implies 
and 
We want to find 
that satisfies both of these conditions. Hence, we can just find the greatest common divisor of the two numbers. 
so the answer is 
~Tacos_are_yummy_1
