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2001 CEMC Gauss (Grade 8) Problems/Problem 13: Difference between revisions

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Thus, after spending money on food and clothing, she had <math>\frac{3}{4} \times \$800 = \$600</math> remaining.
Thus, after spending money on food and clothing, she had <math>\frac{3}{4} \times \$800 = \$600</math> remaining.


She then paid <math>\$350</math> in rent. After that, she had <math>\$600 - \$350 = \$250</math> remaining.
She then paid <math>\$350</math> in rent. After that, she had <math>\$600 - \$350 = \boxed {\textbf {(D) } \$250}</math> remaining.


~anabel.disher
~anabel.disher
{{CEMC box|year=2001|competition=Gauss (Grade 8)|num-b=12|num-a=14}}
{{CEMC box|year=2001|competition=Gauss (Grade 8)|num-b=12|num-a=14}}

Latest revision as of 19:37, 20 October 2025

Problem

Laura earns $\$10$/hour and works $8$ hours per day for $10$ days. She first spends $25\%$ of her pay on food and clothing, and then pays $\$350$ in rent. How much of her pay does she have left?

$\text{ (A) }\ \$275 \qquad\text{ (B) }\ \$200 \qquad\text{ (C) }\ \$350 \qquad\text{ (D) }\ \$250 \qquad\text{ (E) }\ \$300$

Solution 1

First, we can figure out how much money Laura earned from working.

Since she worked $8 \frac{hours}{day}$ for $10 \text{ days}$, we know that she worked $8 \frac{hours}{day} \times 10 \text{ days} = 80 \text{ hours}$ in total.

She earned $\frac{\$10}{hour}$, so she was paid $\frac{\$10}{hour} \times 80 \text { hours} = \$800$ in total.

Next, we can figure out how much money of her pay she has left.

She spent $25\% = \frac{1}{4}$ of her pay on food and clothing, so she had $1 - \frac{1}{4} = \frac{3}{4}$ of her pay remaining after that.

Thus, after spending money on food and clothing, she had $\frac{3}{4} \times \$800 = \$600$ remaining.

She then paid $\$350$ in rent. After that, she had $\$600 - \$350 = \boxed {\textbf {(D) } \$250}$ remaining.

~anabel.disher

2001 CEMC Gauss (Grade 8) (ProblemsAnswer KeyResources)
Preceded by
Problem 12
Followed by
Problem 14
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CEMC Gauss (Grade 8)