2000 CEMC Gauss (Grade 8) Problems/Problem 8: Difference between revisions

Latest revision as of 12:45, 20 October 2025

If $x \ast y = x + y^{2}$ , then $2 \ast 3$ equals

$\text{ (A) }\ 8 \qquad\text{ (B) }\ 25 \qquad\text{ (C) }\ 11 \qquad\text{ (D) }\ 13 \qquad\text{ (E) }\ 7$

We can simply plug in $2$ and $3$ into $x + y^{2}$ :

$2 \ast 3 = 2 + 3^{2} = \boxed {\textbf {(C) } 11}$

~anabel.disher

2000 CEMC Gauss (Grade 8) (Problems • Answer Key • Resources)
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CEMC Gauss (Grade 8)

Revision as of 15:39, 18 June 2025 view source Anabel.disher (talk \| contribs) editor 735 edits Created page with "==Problem== If <math>x \ast y = x + y^{2}</math>, then <math>2 \ast 3</math> equals <math> \text{ (A) }\ 8 \qquad\text{ (B) }\ 25 \qquad\text{ (C) }\ 11 \qquad\text{ (D) }\..."		Latest revision as of 12:45, 20 October 2025 view source Anabel.disher (talk \| contribs) editor 735 edits No edit summary
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			{{CEMC box\|year=2000\|competition=Gauss (Grade 8)\|num-b=7\|num-a=9}}