Art of Problem Solving

Euc20191/Sub-Problem 2: Difference between revisions

Baihly2024 (talk | contribs)
Created page with "==Problem== What integer <math>a</math> satisfies <math>3<\frac{24}{a}<4</math>?"
 
Yuhao2012 (talk | contribs)
No edit summary
 
Line 2: Line 2:


What integer <math>a</math> satisfies <math>3<\frac{24}{a}<4</math>?
What integer <math>a</math> satisfies <math>3<\frac{24}{a}<4</math>?
==Solution==
If <math>a=6</math>, then <math>\frac{24}{6}=4</math> and if <math>a=8</math>, then <math>\frac{24}{8}=3</math>. So, <math>a</math> has to be between <math>6</math> and <math>8</math>, and therefore, it has to be <math>\boxed{7}</math>.
~Yuhao2012

Latest revision as of 10:32, 13 October 2025

Problem

What integer $a$ satisfies $3<\frac{24}{a}<4$?

Solution

If $a=6$, then $\frac{24}{6}=4$ and if $a=8$, then $\frac{24}{8}=3$. So, $a$ has to be between $6$ and $8$, and therefore, it has to be $\boxed{7}$.

~Yuhao2012