1998 CEMC Gauss (Grade 8) Problems/Problem 2: Difference between revisions
Created page with "==Problem== The smallest number in the set <math>\{0, -17, 4, 3, -2\}</math> is <math> \text{ (A) }\ -17 \qquad\text{ (B) }\ 4 \qquad\text{ (C) }\ -2 \qquad\text{ (D) }\ 0..." |
Technodoggo (talk | contribs) m →Solution: -2, not 2 :p |
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<math> \text{ (A) }\ -17 \qquad\text{ (B) }\ 4 \qquad\text{ (C) }\ -2 \qquad\text{ (D) }\ 0 \qquad\text{ (E) }\ 3 </math> | <math> \text{ (A) }\ -17 \qquad\text{ (B) }\ 4 \qquad\text{ (C) }\ -2 \qquad\text{ (D) }\ 0 \qquad\text{ (E) }\ 3 </math> | ||
==Solution== | ==Solution== | ||
The set has negative numbers, meaning any positive numbers or <math>0</math> cannot be the smallest number. This means that all we need to do is compare <math>-17</math> and <math>2</math>. | The set has negative numbers, meaning any positive numbers or <math>0</math> cannot be the smallest number. This means that all we need to do is compare <math>-17</math> and <math>-2</math>. | ||
<math>\boxed {\textbf {(A) } -17}</math> is the smaller of the two. | <math>\boxed {\textbf {(A) } -17}</math> is the smaller of the two. | ||
~anabel.disher | ~anabel.disher | ||
Latest revision as of 23:09, 4 September 2025
Problem
The smallest number in the set 
is
Solution
The set has negative numbers, meaning any positive numbers or 
cannot be the smallest number. This means that all we need to do is compare 
and 
.
is the smaller of the two.
~anabel.disher
