2004 AIME II Problems/Problem 13: Difference between revisions
mNo edit summary |
I like pie (talk | contribs) mNo edit summary |
||
| Line 1: | Line 1: | ||
== Problem == | == Problem == | ||
Let <math> ABCDE </math> be a convex pentagon with <math> AB || CE, BC || AD, AC || DE, \angle ABC=120^\circ, AB=3, BC=5, </math> and <math> | Let <math> ABCDE </math> be a convex pentagon with <math> AB || CE, BC || AD, AC || DE, \angle ABC=120^\circ, AB=3, BC=5, </math> and <math>DE = 15. </math> Given that the ratio between the area of triangle <math> ABC </math> and the area of triangle <math> EBD </math> is <math> m/n, </math> where <math> m </math> and <math> n </math> are relatively prime positive integers, find <math> m+n. </math> | ||
== Solution == | == Solution == | ||
{{solution}} | {{solution}} | ||
== See also == | == See also == | ||
{{AIME box|year=2004|n=II|num-b=12|num-a=14}} | |||
Revision as of 12:25, 19 April 2008
Problem
Let 
be a convex pentagon with 
and 
Given that the ratio between the area of triangle 
and the area of triangle 
is 
where 
and 
are relatively prime positive integers, find 
Solution
This problem needs a solution. If you have a solution for it, please help us out by adding it.
See also
| 2004 AIME II (Problems • Answer Key • Resources) | ||
| Preceded by Problem 12 |
Followed by Problem 14 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
| All AIME Problems and Solutions | ||
