2001 AMC 12 Problems: Difference between revisions
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== Problem 5 == | == Problem 5 == | ||
What is the product of all positive odd integers less than 10000? | |||
<math>\text{(A)}\ \dfrac{10000!}{(5000!)^2}\qquad \text{(B)}\ \dfrac{10000!}{2^{5000}}\qquad | |||
\text{(C)}\ \dfrac{9999!}{2^{5000}}\qquad \text{(D)}\ \dfrac{10000!}{2^{5000} \cdot 5000!}\qquad | |||
\text{(E)}\ \dfrac{5000!}{2^{5000}}</math> | |||
[[2001 AMC 12 Problems/Problem 5|Solution]] | [[2001 AMC 12 Problems/Problem 5|Solution]] | ||
Revision as of 13:18, 16 February 2008
Problem 1
The sum of two numbers is
. Suppose
is added to each number and then
each of the resulting numbers is doubled. What is the sum of the final two
numbers?
Problem 2
Let
and
denote the product and the sum, respectively, of the digits
of the integer
. For example,
and
. Suppose
is a
two-digit number such that
. What is the units digit of
?
Problem 3
The state income tax where Kristin lives is levied at the rate of $p%$ (Error compiling LaTeX. Unknown error_msg) of the first
<dollar/>
of annual income plus $(p + 2)%$ (Error compiling LaTeX. Unknown error_msg) of any amount above <dollar/>
. Kristin
noticed that the state income tax she paid amounted to $(p + 0.25)%$ (Error compiling LaTeX. Unknown error_msg) of her
annual income. What was her annual income?
<dollar/>
<dollar/>
<dollar/>
<dollar/>
<dollar/>
Problem 4
The mean of three numbers is
more than the least of the numbers and
less than the greatest. The median of the three numbers is
. What is their
sum?
Problem 5
What is the product of all positive odd integers less than 10000?