2007 AMC 10A Problems/Problem 18: Difference between revisions
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==Problem== | |||
Consider the <math>12</math>-sided polygon <math>ABCDEFGHIJKL</math>, as shown. Each of its sides has length <math>4</math>, and each two consecutive sides form a right angle. Suppose that <math>\overline{AG}</math> and <math>\overline{CH}</math> meet at <math>M</math>. What is the area of quadrilateral <math>ABCM</math>? | |||
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<math>\text{(A)}\ \frac {44}{3}\qquad \text{(B)}\ 16 \qquad \text{(C)}\ \frac {88}{5}\qquad \text{(D)}\ 20 \qquad \text{(E)}\ \frac {62}{3}</math> | |||
==Solution== | |||
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==See also== | |||
Revision as of 08:53, 5 February 2008
Problem
Consider the 
-sided polygon 
, as shown. Each of its sides has length 
, and each two consecutive sides form a right angle. Suppose that 
and 
meet at 
. What is the area of quadrilateral 
?
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Solution
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