2004 AMC 12A Problems/Problem 2: Difference between revisions
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==Problem== | ==Problem== | ||
On the AMC 12, each correct answer is worth <math>6</math> points, each incorrect answer is worth <math>0</math> points, and each problem left unanswered is worth <math>2.5</math> points. If Charlyn leaves <math>8</math> of the <math>25</math> problems unanswered, how many of the remaining problems must she answer correctly in order to score at least <math>100</math>? | |||
{{ | <math>\text {(A)} 11 \qquad \text {(B)} 13 \qquad \text {(C)} 14 \qquad \text {(D)} 16\qquad \text {(E)}17</math> | ||
==Solution== | ==Solution== | ||
{{ | She gets <math>8*2.5=20</math> points for the problems she didn't answer. She must get <math>\lceil \frac{100-20}{6} \rceil =14 \Rightarrow \text {(D)}</math> problems right to score at least 100. | ||
==See Also== | ==See Also== | ||
{{AMC12 box|year=2004|ab=A|num-b=1|num-a=3}} | {{AMC12 box|year=2004|ab=A|num-b=1|num-a=3}} | ||
[[Category:Introductory Algebra Problems]] | |||
Revision as of 07:55, 18 January 2008
Problem
On the AMC 12, each correct answer is worth 
points, each incorrect answer is worth 
points, and each problem left unanswered is worth 
points. If Charlyn leaves 
of the 
problems unanswered, how many of the remaining problems must she answer correctly in order to score at least 
?
Solution
She gets 
points for the problems she didn't answer. She must get 
problems right to score at least 100.
See Also
| 2004 AMC 12A (Problems • Answer Key • Resources) | |
| Preceded by Problem 1 |
Followed by Problem 3 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
