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2002 AMC 10P Problems/Problem 2: Difference between revisions

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#REDIRECT [[2002 AMC 12P Problems/Problem 2]]
== Problem 2 ==
The sum of eleven consecutive integers is <math>2002.</math> What is the smallest of these integers?
 
<math>
\text{(A) }175
\qquad
\text{(B) }177
\qquad
\text{(C) }179
\qquad
\text{(D) }180
\qquad
\text{(E) }181
</math>
 
== Solution 1 ==
 
== See Also ==

Revision as of 06:48, 15 July 2024

Problem 2

The sum of eleven consecutive integers is $2002.$ What is the smallest of these integers?

$\text{(A) }175 \qquad \text{(B) }177 \qquad \text{(C) }179 \qquad \text{(D) }180 \qquad \text{(E) }181$

Solution 1

See Also

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