Art of Problem Solving

1970 AMC 12 Problems/Problem 2: Difference between revisions

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A square and a circle have equal perimeters. The ratio of the area of the circle to the area of the square is
A square and a circle have equal perimeters. The ratio of the area of the circle to the area of the square is


<math>\mathrm{(A)}\ \frac 2\pi\qquad \mathrm{(B)}\ \frac pi\root2\qquad \mathrm{(C)}\ \frac 45\qquad \mathrm{(D)}\ \frac 56\qquad \mathrm{(E)}\ \frac 78</math>
<math>\mathrm{(A)}\ \frac 2\pi\qquad \mathrm{(B)}\ \frac pi\2\qquad \mathrm{(C)}\ \frac 45\qquad \mathrm{(D)}\ \frac 56\qquad \mathrm{(E)}\ \frac 78</math>


== Solution ==
== Solution ==

Revision as of 11:36, 9 January 2008

Problem

A square and a circle have equal perimeters. The ratio of the area of the circle to the area of the square is

$\mathrm{(A)}\ \frac 2\pi\qquad \mathrm{(B)}\ \frac pi\2\qquad \mathrm{(C)}\ \frac 45\qquad \mathrm{(D)}\ \frac 56\qquad \mathrm{(E)}\ \frac 78$ (Error compiling LaTeX. Unknown error_msg)

Solution