1970 AMC 12 Problems/Problem 2: Difference between revisions
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A square and a circle have equal perimeters. The ratio of the area of the circle to the area of the square is | A square and a circle have equal perimeters. The ratio of the area of the circle to the area of the square is | ||
<math> \mathrm{(A) \ | <math>\mathrm{(A)}\ \frac 2pi\qquad \mathrm{(B)}\ \frac 34\qquad \mathrm{(C)}\ \frac 45\qquad \mathrm{(D)}\ \frac 56\qquad \mathrm{(E)}\ \frac 78</math> | ||
== Solution == | == Solution == | ||
Revision as of 11:34, 9 January 2008
Problem
A square and a circle have equal perimeters. The ratio of the area of the circle to the area of the square is