1970 AMC 12 Problems/Problem 2: Difference between revisions
New page: A square and a circle have equal perimeters. The ratio of the area of the circle to the area of the square is |
No edit summary |
||
| Line 1: | Line 1: | ||
== Problem == | |||
A square and a circle have equal perimeters. The ratio of the area of the circle to the area of the square is | A square and a circle have equal perimeters. The ratio of the area of the circle to the area of the square is | ||
<math> \mathrm{(A) \ } -h\qquad \mathrm{(B) \ } 0\qquad \mathrm{(C) \ } h\qquad \mathrm{(D) \ } 2h</math> | |||
<math>\mathrm{(E) \ } h^3</math> | |||
== Solution == | |||
Revision as of 11:29, 9 January 2008
Problem
A square and a circle have equal perimeters. The ratio of the area of the circle to the area of the square is
