2024 USAMO Problems/Problem 5: Difference between revisions
| Line 6: | Line 6: | ||
== Solution 1 == | == Solution 1 == | ||
Let <math>\angle DBT = \alpha</math> and <math>\angle BEM = \beta</math>. | |||
Extend AD intersects BC at point T, then TC = TA, TE is perpendicular to AC | Extend AD intersects BC at point T, then TC = TA, TE is perpendicular to AC | ||
Thus, AB is the tangent of the circle BEM | Thus, AB is the tangent of the circle BEM | ||
Then the question is equivalent as the angle ABT is the auxillary angle of | Then the question is equivalent as the <math>\angle ABT</math> is the auxillary angle of <math>\angle BEM</math>. | ||
continue | continue | ||
Revision as of 21:53, 16 May 2024
- The following problem is from both the 2024 USAMO/5 and 2024 USAJMO/6, so both problems redirect to this page.
Problem
Point 
is selected inside acute triangle 
so that 
and 
. Point 
is chosen on ray 
so that 
. Let 
be the midpoint of 
. Show that line 
is tangent to the circumcircle of triangle 
.
Solution 1
Let 
and 
.
Extend AD intersects BC at point T, then TC = TA, TE is perpendicular to AC
Thus, AB is the tangent of the circle BEM
Then the question is equivalent as the 
is the auxillary angle of 
.
continue
See Also
| 2024 USAMO (Problems • Resources) | ||
| Preceded by Problem 4 |
Followed by Problem 6 | |
| 1 • 2 • 3 • 4 • 5 • 6 | ||
| All USAMO Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America. 
