2024 AIME II Problems/Problem 15: Difference between revisions
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Problem: Suppose we have <math>69</math> chicken eggs and <math>696</math> egg eggs. Find the square root of the total number of true eggs that are 69able. | Problem: Suppose we have <math>69</math> chicken eggs and <math>696</math> egg eggs. Find the square root of the total number of true eggs that are 69able. | ||
Solution: Using the <cmath>Egger's Eg(g)regious Eggo Eggnog Egg law</cmath>, we can use the <math>Monkey Math Law</math> to find the total number of true eggs. Thus, we have 69696 total true eggs that are 69able. Then we square root and this yields <math>\boxed{264}</math>. | Solution: | ||
Using the <cmath>Egger's Eg(g)regious Eggo Eggnog Egg law</cmath>, we can use the <math>Monkey Math Law</math> to find the total number of true eggs. Thus, we have 69696 total true eggs that are 69able. Then we square root and this yields <math>\boxed{264}</math>. | |||
Revision as of 00:38, 24 January 2024
Problem: Suppose we have 
chicken eggs and 
egg eggs. Find the square root of the total number of true eggs that are 69able.
Solution:
Using the ![\[Egger's Eg(g)regious Eggo Eggnog Egg law\]](http://latex.artofproblemsolving.com/a/b/d/abd4034a79da22ab508594f2980ea20dc8f8d287.png)
, we can use the 
to find the total number of true eggs. Thus, we have 69696 total true eggs that are 69able. Then we square root and this yields 
.
