2023 AMC 10B Problems/Problem 8: Difference between revisions
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==Solution== | ==Solution== | ||
<math>2022^{2023} + 2023^{2022} \equiv 2^3 + 3^2 \equiv 17 \equiv 7</math> (mod 10). <math>\boxed{\text{B}}</math> | <math>2022^{2023} + 2023^{2022} \equiv 2^3 + 3^2 \equiv 17 \equiv 7</math> (mod 10). <math>\boxed{\text{B}}</math> | ||
~andliu766 | |||
Revision as of 15:26, 15 November 2023
What is the units digit of 
?
Solution
(mod 10). 
~andliu766
