2003 AIME II Problems/Problem 10: Difference between revisions
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== Problem == | == Problem == | ||
Two positive integers differ by <math>60.</math> The sum of their square roots is the square root of an integer that is not a perfect square. What is the maximum possible sum of the two integers? | |||
== Solution == | == Solution == | ||
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== See also == | == See also == | ||
{{AIME box|year=2003|n=II|num-b=9|num-a=11}} | |||
Revision as of 13:40, 21 November 2007
Problem
Two positive integers differ by 
The sum of their square roots is the square root of an integer that is not a perfect square. What is the maximum possible sum of the two integers?
Solution
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See also
| 2003 AIME II (Problems • Answer Key • Resources) | ||
| Preceded by Problem 9 |
Followed by Problem 11 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
| All AIME Problems and Solutions | ||
