Art of Problem Solving

1985 AJHSME Problem 17: Difference between revisions

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Created page with "== Problem == If your average score on your first six mathematics tests was <math>84</math> and your average score on your first seven mathematics tests was <math>85</math>, t..."
 
 
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<math>\text{(A)}\ 86 \qquad \text{(B)}\ 88 \qquad \text{(C)}\ 90 \qquad \text{(D)}\ 91 \qquad \text{(E)}\ 92</math>
<math>\text{(A)}\ 86 \qquad \text{(B)}\ 88 \qquad \text{(C)}\ 90 \qquad \text{(D)}\ 91 \qquad \text{(E)}\ 92</math>
==In-depth Solution by BoundlessBrain!==
https://youtu.be/EIoCLu2wR88


== Solution ==
== Solution ==
The total score of your first 6 tests was <math>84 \cdot 6 = 504</math> and the total score of your first 7 tests was <math>85 \cdot 7 = 595.</math> So, the missing score is <math>595-504 = \boxed{\text{(D)} \quad 91}.</math>
The total score of your first 6 tests was <math>84 \cdot 6 = 504</math> and the total score of your first 7 tests was <math>85 \cdot 7 = 595.</math> So, the missing score is <math>595-504 = \boxed{\text{(D)} \quad 91}.</math>

Latest revision as of 15:01, 4 July 2023

Problem

If your average score on your first six mathematics tests was $84$ and your average score on your first seven mathematics tests was $85$, then your score on the seventh test was

$\text{(A)}\ 86 \qquad \text{(B)}\ 88 \qquad \text{(C)}\ 90 \qquad \text{(D)}\ 91 \qquad \text{(E)}\ 92$

In-depth Solution by BoundlessBrain!

https://youtu.be/EIoCLu2wR88

Solution

The total score of your first 6 tests was $84 \cdot 6 = 504$ and the total score of your first 7 tests was $85 \cdot 7 = 595.$ So, the missing score is $595-504 = \boxed{\text{(D)} \quad 91}.$