1959 AHSME Problems/Problem 22: Difference between revisions
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== Solution == | |||
Let x be the length of the shorter base. | Let x be the length of the shorter base. | ||
3 = (97 - x)/2 | 3 = (97 - x)/2 | ||
Revision as of 18:12, 7 April 2023
Solution
Let x be the length of the shorter base. 3 = (97 - x)/2
6 = 97 - x
x = 91
Thus, 91.
